#3

3 things that are important in interviewing
Paying attention to how a question is answered
As a journalist you must ask embarrassing questions sometimes but don't pry and don't snoop, ask hostile or loaded questions.
Prepare question BEFORE the interview

2 things I will try to do in the future
Go to the Primary source for information
Will not argue with my subject but rather listen

1 thing you think sounded silly/stupid/unnecessary (site the pg. # from the book)
Page 100- Student journalists often are advised to avoid asking embarrassing questions.

Finding Zeros

FACTORING (Notes)

x^3+ 5x^2-4x-20
x^2(x-5)-4(x+5)
(x+5)(x^2-4)
(x+5)(x-2)(x+2)

Zeros for this Polynominal are: (-5,0)(2,0)(-2,0)

x^3+4x^2-9x-36
x^2(x+4)-9(x+4)
(x^2-9)(x+4)
(x-3)(x+3)(x+4)
Zeros for this Polynominals: (3,0)(-3,0)(-4,0)

-----------------------------------------------------
#1 LET y=x^2 & y^2 =x^4

2x^4 -x^2-3
2y^2-y-3
(2y-3)(y+1)
2y-3=0 or y+1=0
y=1.5 or y=1

x^2=1.5 or x^2=-1


#2

x^4-5x^2+4
y^2-5y+4
(y-4)(y-1)
y-4=0 or y-1=0
y=4 or y=1
x^2=4 or x^2=1
x=+/-2 or x=+/-1
(x+2)(x-2)(x+1)(x-1)

NOTES FOR 11-1-2010

BELL RINGER

Classify the following polynomials as

A.) Quadratic

B.) Cubic

C.) Quartic

D.) Quintic

1.) X^3-X^2+2

2.) X^5+6X^3-4

3.) X^2

4.) X^4-2X^2+2X

AGENDA

I. Bell Ringer

II. Solving Polynomialsusing synthetic substitution

Objective: Students will classify and solve polynomials

Big Picture: Data from science, business, and engineering can be modeled using polynomial curves

NOTES

Polynomials - one or more terms of an algebraic expression

Degree of a Polynomial- is defined by the largest exponent of the variable

EX.

3X^3 <------ Degree 3

3^3X <------ Degree 1

A polynomial with degree 3 can have at MOST 4 terms

Ax^3+Bx^2+Cx+D

Ax^3=first term

Bx^2=second term

Cx=third term

D=forth term

Synthetic Substitution- Is a method for solving any polynomial for a given value

P(X)= 3X^4-7X^3-5X^2+9X+10

P(2)=3(2)^4-7(2)^3-5(2)^2+9(2)+10

P(2)= 0

2_l 3 -7 -5 9 10

6 -2 -14 10

------------------------

3 -6 7 -5 20

the test was insane I do not know if I did good or bad on it

Notes from 10-27-10

Bell Ringer

pg 47 #15

Agenda
I. Bell Ringer
II. Chapter 1 Review

Objective: Students will demonstrate knowledge of linear and quadratic equations.

Big Picture: Linear and quadratic functions model objects in motion and financial applications.

Reminder: There is a test on Thursday October 28. Be prepared.

Question of the Day: Today we had to look in our books for the bell ringer; how many of you actually bring your book to class so that you can see the problem?

what's up?!

ok so this lesson was a little easier than what we were learning previous to this!

melania gomez (agenda)

Write in the vertex from and name the Vertex
x^2-6x+2 x^2-8x+5

Agenda
I BELL RINGER
II HOMEWORK REVIEW
III GRAPH QUADRATIC FUNCTION

OBJECTIVE- Student will graph quadratic function and plot
( The vertex, zeros, y-intercept and axis of symmetry)
Big picture- Quadratic functions Model objects in motion.

#9
x^2-2x-7
(x^2-2x+1) -7-1
(x-1) (x-1)-6 since -2 is equal by -1, it would be x-1 twice because it would equal -2x
(x-1)^2-6 then you bring down the -7 and add the opposite of +1 to -1.
(1,-8)

4x^2-8x+2
4(x^2-2x+1)+2-1 the 4 is not really useful because we would want the to leave it out, to
4(x-1) (x-1)+1 make it "skinny", yet always bring it down, with the rest of the problem
4(x-1)(x-1)+1 shown on your left.
4(x-1)^2+1
(1,1)

#13
y=1/2x^2+4x+8
1/2(x^2+8x+16)+8-16 The 8 is equal from 4 twice, which it would be x+4 twice. Also since
1/2(x+4) (x+4)-8 4x4=16 we would put +16 then finish the (), which bring down 8 and
1/2(x-4)^2-8 add opposite of 16 to -16, to finish the second part. then the 1/2 just
(-4,-8) bring down and would not be touched in this problem because
we would want it "skinny"
The homework for today is pg. 41 (15-20)
find the
1 y-intercept
2 zeros
3 vertex

a b c
1. f(x)=x^2-6x+8
6/36-4*8
6+2 or 6-2 which also 4 or 2 y-intercept (0,8)
2 2

2. (x^2-6x+9)+8-9
(x-3) (x-3)-1
(x-3)^2-1
(4,0) (2,0)