#3

3 things that are important in interviewing
Paying attention to how a question is answered
As a journalist you must ask embarrassing questions sometimes but don't pry and don't snoop, ask hostile or loaded questions.
Prepare question BEFORE the interview

2 things I will try to do in the future
Go to the Primary source for information
Will not argue with my subject but rather listen

1 thing you think sounded silly/stupid/unnecessary (site the pg. # from the book)
Page 100- Student journalists often are advised to avoid asking embarrassing questions.

Finding Zeros

FACTORING (Notes)

x^3+ 5x^2-4x-20
x^2(x-5)-4(x+5)
(x+5)(x^2-4)
(x+5)(x-2)(x+2)

Zeros for this Polynominal are: (-5,0)(2,0)(-2,0)

x^3+4x^2-9x-36
x^2(x+4)-9(x+4)
(x^2-9)(x+4)
(x-3)(x+3)(x+4)
Zeros for this Polynominals: (3,0)(-3,0)(-4,0)

-----------------------------------------------------
#1 LET y=x^2 & y^2 =x^4

2x^4 -x^2-3
2y^2-y-3
(2y-3)(y+1)
2y-3=0 or y+1=0
y=1.5 or y=1

x^2=1.5 or x^2=-1


#2

x^4-5x^2+4
y^2-5y+4
(y-4)(y-1)
y-4=0 or y-1=0
y=4 or y=1
x^2=4 or x^2=1
x=+/-2 or x=+/-1
(x+2)(x-2)(x+1)(x-1)

NOTES FOR 11-1-2010

BELL RINGER

Classify the following polynomials as

A.) Quadratic

B.) Cubic

C.) Quartic

D.) Quintic

1.) X^3-X^2+2

2.) X^5+6X^3-4

3.) X^2

4.) X^4-2X^2+2X

AGENDA

I. Bell Ringer

II. Solving Polynomialsusing synthetic substitution

Objective: Students will classify and solve polynomials

Big Picture: Data from science, business, and engineering can be modeled using polynomial curves

NOTES

Polynomials - one or more terms of an algebraic expression

Degree of a Polynomial- is defined by the largest exponent of the variable

EX.

3X^3 <------ Degree 3

3^3X <------ Degree 1

A polynomial with degree 3 can have at MOST 4 terms

Ax^3+Bx^2+Cx+D

Ax^3=first term

Bx^2=second term

Cx=third term

D=forth term

Synthetic Substitution- Is a method for solving any polynomial for a given value

P(X)= 3X^4-7X^3-5X^2+9X+10

P(2)=3(2)^4-7(2)^3-5(2)^2+9(2)+10

P(2)= 0

2_l 3 -7 -5 9 10

6 -2 -14 10

------------------------

3 -6 7 -5 20

the test was insane I do not know if I did good or bad on it

Notes from 10-27-10

Bell Ringer

pg 47 #15

Agenda
I. Bell Ringer
II. Chapter 1 Review

Objective: Students will demonstrate knowledge of linear and quadratic equations.

Big Picture: Linear and quadratic functions model objects in motion and financial applications.

Reminder: There is a test on Thursday October 28. Be prepared.

Question of the Day: Today we had to look in our books for the bell ringer; how many of you actually bring your book to class so that you can see the problem?

what's up?!

ok so this lesson was a little easier than what we were learning previous to this!

melania gomez (agenda)

Write in the vertex from and name the Vertex
x^2-6x+2 x^2-8x+5

Agenda
I BELL RINGER
II HOMEWORK REVIEW
III GRAPH QUADRATIC FUNCTION

OBJECTIVE- Student will graph quadratic function and plot
( The vertex, zeros, y-intercept and axis of symmetry)
Big picture- Quadratic functions Model objects in motion.

#9
x^2-2x-7
(x^2-2x+1) -7-1
(x-1) (x-1)-6 since -2 is equal by -1, it would be x-1 twice because it would equal -2x
(x-1)^2-6 then you bring down the -7 and add the opposite of +1 to -1.
(1,-8)

4x^2-8x+2
4(x^2-2x+1)+2-1 the 4 is not really useful because we would want the to leave it out, to
4(x-1) (x-1)+1 make it "skinny", yet always bring it down, with the rest of the problem
4(x-1)(x-1)+1 shown on your left.
4(x-1)^2+1
(1,1)

#13
y=1/2x^2+4x+8
1/2(x^2+8x+16)+8-16 The 8 is equal from 4 twice, which it would be x+4 twice. Also since
1/2(x+4) (x+4)-8 4x4=16 we would put +16 then finish the (), which bring down 8 and
1/2(x-4)^2-8 add opposite of 16 to -16, to finish the second part. then the 1/2 just
(-4,-8) bring down and would not be touched in this problem because
we would want it "skinny"
The homework for today is pg. 41 (15-20)
find the
1 y-intercept
2 zeros
3 vertex

a b c
1. f(x)=x^2-6x+8
6/36-4*8
6+2 or 6-2 which also 4 or 2 y-intercept (0,8)
2 2

2. (x^2-6x+9)+8-9
(x-3) (x-3)-1
(x-3)^2-1
(4,0) (2,0)

MWAHAHAHAHAH

Finally Ms. Sullivan!!!!!!!!!!!!!!!

Just commenting so i can get my points.

Notes for 10/06/2010

''''''''___
i=-/-1
i2=-1
i3=-i
i4=1

Bell Ringer

3+4i...(2+i)
-----...------
(2-i)...(2+i)

4-2i+2i-i2
4-(-1)=5
6+3i+8i+4i2
6+11i+4(-1)
6-4+11i

2+11i
-------
...5

i2+2i3.....i
--------..---
.....i.........i

i3+2i4
-------
...i2

-i+2
------
...i

-1
---
-1

(2-i)
-----
.-1

-2+i

H.W.
Page. 28
#19-30
-try useing a calculater

Agenda
I Bell Ringer
II Finding and Manipulating Complex Conjugates
III Factoring of Quadratic Functions


Objective: Students will find and manipulate complex conjugates

Big Picture: Mathematics will find a solution to the unsolvable. Even if they have to make it up.


Bell Ringer

Using the quadratic formula
- Find the zeros in:
10x^2-5x+20
2x^2+4x+15

answers:
1+- square root of 31i /4
-4+-2 square root of 26i / 4


ex 1- add
4 + 2i
+ ( 7 - 3i )
------------
11 - 1i

ex 2- subtract
7 + 8i
- ( 8 + 2i )
-----------
-1 + 6i

ex 3- multiply
( 7 + 8i ) ( 7 - 8i )
49 - 56i + 56i - 64 (i^2)
49 + 64 = 113


ex 4- divide
3 + 4i (2 + 5i)
____ _____
2 - 5i (2 + 5i)

*do the distributive property or f.o.i.l.
-14 + 23
______
29

Homework- page 28 #'s 1-10

lost

what is the post for today??

im confused with the domain and stuff. i don't know how to do the hw

why isn't there a blog for today?

Notes for 9-29-10

Agenda

I bell ringer

II linear function

III domain and range

Objective: students will define functions and identify domains

big picture: linear functions can be used to model real world situations

Page 24 # 18 Example

$ 12000 cost of computer

depreciate by 10% of the purchase price each year. annually $1200

V(y)=-1200y+12000

What is the computer worth after 3 years

V(3)=-1200(3)+12000

V(3)=$8400

Range and domain

valid input

(x)

0 is less than or equal to y is less than or equal to 10

input

0 less than or equal to p() is less than or equal to12000

answer

HOMEWORK IS PAGE 24 #18,20,21

???

i still dont completly understand how to do the homework....help??

where are the notes for today

???

What do we comment on?

this is a pain in the bum>_<

i am not following anything in class and I can't find any of the bloggers posts from last week. I am unhappy. very unhappy:((((

Who was in charge of the blog. i have no clue of what we were doing with the functions stuff. i kind of understand it but then i don't.

why isn't there a blog from Wednesday or today...this things so confusing....

more explanation needs to be going on in class....

hey

honestly i dont understand what is being taught in this class.
what could i possibly do to understand/bring my grade up??

hey

I hope I get some points for doing this!!!! Dakota

Homework

why does the book have any examples of how to do problems that are given in the homework assigment

melania gomez

the home work for today is page 23 (11-14) , mostly the same homework from yesterday. and she might collect the homework tomorrow MAYBE.

Pre-Cal Notes 9/21/10 Period 3

1. Bell Ringer
2. Go over Quiz
3. No Homework

• Example #3: C(m)= 580(m)= $2,000

Input is positive intergers: domain.

Outpt is positive intergers greater than or equal to $2,000: range.

soooooo...

any homework today?

Homework

Was there any homework assigned for today???

??

what was the homework assigned yesterday?? where are the notes?

what up miss ssssssssssssssssss.....

I don't get the homework at all. How I am supose to do it

Where are the notes from yesterday? that's what I need help with, I think. i forgot if that was when we did the functions.
Mercedes Reyes

It's going to be 50 tickets to tie the sum and 51 to make profit

9/15/2010

Agenda
i. Bell Ringer
ii. Home Work Review
iii. Linear Equations

Objective: Students will be able to model real world situations as linear functions.

i. Bell Ringer

find the equation of the two points (3,5)(2,1)

m=1-5 =-4 4 being you slope
---- --- = 4
2-3 -1


So now plug it in
y-y1=m(x-x1)
y-5=4(x-3)
y-5=4x-12
y=4x-7
* both in bold could be used as a answer

Find the equation of a parallel line
- since its parallel it has the same slope
y=4x-8 <<
Find the equation of a line to (-8,4)
y-4=--1/4(x- -8)
y - 4 = -1/4 (x + 8)
y - 4 = -1/4x - 2
y=-1/4+2


ii. Home Work Review
5.
(-1,4) (5,-8) find the slope

8 - 4 4 2
----- = -- = --
5 +1 6 3
y-4 = 2/3 (x+1)

7.
(5,-7)
if its horizontal y stays the same
y = -7
if its a vertical x stays the same
x= 5
14.
x-3y = 9
-x -x
-3y = -x +9
---- ------
-3 -3 -3

y= 1/3x -3

9.
(2,-7) (2,3)
if m is undefined the equations is xb

I'M NOT ADDING THE LAST 2

iii. pg 19 Linear Functions
f (x) = 1x+3
g(x) = 3x-2
l(T) = 0.0001T+10
g(s) = -1.2s +4.7
h(t) = 3


pg. 20
Rent was $200 p= profit
Tickets were $5
p(t) = 5t - 200 t= tickets
0>5t - 200
+200 + 200

200>5t
--- --
5 5
40>t



-------------------------------------------------------
Question;
1. How many people a dropping this class? (j/k)

2. If I'm throwing a party and I have to pay 150 for the dj , 200 for the location and and 150 food how many $10 tickets do I have to sell to start making a profit?
--------------------------------------------------------

this took forever =[

Natalia Buza

9-14-10

Objective: Students will be able to find parallel and perpendicular lines to a given line.

Parallel:
y=5x+7
y=5x+2
y=5x+1
y=5x-1,000,000,000

**If they have the same slope their parallel

y=3x+2
y=1/3x
(2,-4)- point of intersection
-4=1/3(2)+b
-4=2/3+b
-42/3=b

2 ways to find where perpendicular intersect
1st-subtract

y=4x+5
-(y=-1/4x+3)
--------------
0=4.25x+2
-2 -2
--------------
-2 = 4.25x
--- -----
4.25 4.25

-200 = -8
----- ---
425 17

y=4(8/17)+5
=53
--
17
(-8/17, 53/17)

2nd way:calculator

4x-y=-5
-1/4x-y=-3
[4 -1 -5
-1/4 -1 -3]

hw: pg 16 5-14

Michelle Ramirez September 13, 2010

Notes- Solving systems of equations

3x+5y=7
2x-4y=2

1.intersect at 1 and only one point
2.infinitely many-some lin
3.never intersect-parallel line

Calculator
1.2nd
2.matrix
3.edit
4.enter matrix[A] 2x3 [3 5 7]
[2 14 2]

Tytiana Whiteside Sept.10, 2010


Y-intercept
y=mx+b (m-slope)(b-y intercept)

Standard Form
Ax+By=C

Point Slope Form
Y-Y1=m(x-x1) (m-slope)

Given Segment Line AB A=(-5,2) B=(-7,8)
To find the midpoint
(x1+x2/2, y1+y2/2)
(-7+-5/2, 2+8/2) =(-6,5)

To find the distance
d=The square root of (x2-x1) to the 2nd power + (y2-y1) to the 2nd power
d= The square root of (2) to the 2nd power + (-6) to the 2nd power
4+36
d= square root of 40
d=2 the square root of 10
Ax+By=C
Matrix Function
2nd Maqtrix
Edit 2x3
3x+7y=-5
2x-4y=2
[3 7 -5]
[2 -4 2]

2nd Quit
2nd Matrix
Math
rref (B0
2nd Matrix
rref ([A])
[1 0 -3/13]
[0 1 -8/13]


Homework page 4 #1-8

HEy yall.!

Michelle Ramirez

hey

today i learned how to use a calculator. yay!!!

Finally!! Hey Ms. Sullivan!

HI CORY!!!!!!!! =D

heyy

i got it to work

Hey!

So the invitation finally worked! Thanks Mrs. Sullivan! :)

Heyyy!!!

I finally got in... Thanks Ms. Sullivan! See you tomorrow in class..

Wassup ..

Hi.. Ms. Sullivan !!!!

Itz Manny Martinez !!!!

Hi.. Ms. Sullivan !!!!

Hellooo[:

Finally in!

Jazmin Salgado.

Hey =]

Finally in.

Finally

This is me Adrian I finally loged in

AYE im in heaaa! Jordyn Bailey 3rd period.

hey

finally here..

Melania Gomez

Author

Finally got in!
Celeise Sanchez

Hii i finally got in
yadira olea

IM IN!
NATHAN DAVILA!

Wats up Oscar zarate

Wat up

Natalia Buza
Third Period

Author

Good night everybody.
-Stefania D.

author

Olga Bustamante 3

Author

Jennifer Maravillas 3rd period

author

hello;]

Michelle Ramirez

Author

I did it! :)

Gimmie my points!

Lukasz Krawiec

Auther

Hi,

Leomely Ramos 3

author

victor jimenez 3rd period

Author

Heyyyyyyyyyyyyyyyyyyyyyyyyyyyyy

Welcome

Each day a student will be assigned to post to the Precalculus blog.  In this blog you will share:

1.  The Agenda for the day
2.  Notes from the Class
3. The homework assignment
4.  Hints or suggestions
5. One thing you want to share about the lesson