Wednesday, October 27, 2010
Notes from 10-27-10
Bell Ringer
pg 47 #15
pg 47 #15
Agenda
I. Bell Ringer
II. Chapter 1 Review
Objective: Students will demonstrate knowledge of linear and quadratic equations.
Big Picture: Linear and quadratic functions model objects in motion and financial applications.
Reminder: There is a test on Thursday October 28. Be prepared.
Question of the Day: Today we had to look in our books for the bell ringer; how many of you actually bring your book to class so that you can see the problem?
I. Bell Ringer
II. Chapter 1 Review
Objective: Students will demonstrate knowledge of linear and quadratic equations.
Big Picture: Linear and quadratic functions model objects in motion and financial applications.
Reminder: There is a test on Thursday October 28. Be prepared.
Question of the Day: Today we had to look in our books for the bell ringer; how many of you actually bring your book to class so that you can see the problem?
Wednesday, October 20, 2010
Tuesday, October 19, 2010
melania gomez (agenda)
Write in the vertex from and name the Vertex
x^2-6x+2 x^2-8x+5
Agenda
I BELL RINGER
II HOMEWORK REVIEW
III GRAPH QUADRATIC FUNCTION
OBJECTIVE- Student will graph quadratic function and plot
( The vertex, zeros, y-intercept and axis of symmetry)
Big picture- Quadratic functions Model objects in motion.
#9
x^2-2x-7
(x^2-2x+1) -7-1
(x-1) (x-1)-6 since -2 is equal by -1, it would be x-1 twice because it would equal -2x
(x-1)^2-6 then you bring down the -7 and add the opposite of +1 to -1.
(1,-8)
4x^2-8x+2
4(x^2-2x+1)+2-1 the 4 is not really useful because we would want the to leave it out, to
4(x-1) (x-1)+1 make it "skinny", yet always bring it down, with the rest of the problem
4(x-1)(x-1)+1 shown on your left.
4(x-1)^2+1
(1,1)
#13
y=1/2x^2+4x+8
1/2(x^2+8x+16)+8-16 The 8 is equal from 4 twice, which it would be x+4 twice. Also since
1/2(x+4) (x+4)-8 4x4=16 we would put +16 then finish the (), which bring down 8 and
1/2(x-4)^2-8 add opposite of 16 to -16, to finish the second part. then the 1/2 just
(-4,-8) bring down and would not be touched in this problem because
we would want it "skinny"
The homework for today is pg. 41 (15-20)
find the
1 y-intercept
2 zeros
3 vertex
a b c
1. f(x)=x^2-6x+8
6/36-4*8
6+2 or 6-2 which also 4 or 2 y-intercept (0,8)
2 2
2. (x^2-6x+9)+8-9
(x-3) (x-3)-1
(x-3)^2-1
(4,0) (2,0)
x^2-6x+2 x^2-8x+5
Agenda
I BELL RINGER
II HOMEWORK REVIEW
III GRAPH QUADRATIC FUNCTION
OBJECTIVE- Student will graph quadratic function and plot
( The vertex, zeros, y-intercept and axis of symmetry)
Big picture- Quadratic functions Model objects in motion.
#9
x^2-2x-7
(x^2-2x+1) -7-1
(x-1) (x-1)-6 since -2 is equal by -1, it would be x-1 twice because it would equal -2x
(x-1)^2-6 then you bring down the -7 and add the opposite of +1 to -1.
(1,-8)
4x^2-8x+2
4(x^2-2x+1)+2-1 the 4 is not really useful because we would want the to leave it out, to
4(x-1) (x-1)+1 make it "skinny", yet always bring it down, with the rest of the problem
4(x-1)(x-1)+1 shown on your left.
4(x-1)^2+1
(1,1)
#13
y=1/2x^2+4x+8
1/2(x^2+8x+16)+8-16 The 8 is equal from 4 twice, which it would be x+4 twice. Also since
1/2(x+4) (x+4)-8 4x4=16 we would put +16 then finish the (), which bring down 8 and
1/2(x-4)^2-8 add opposite of 16 to -16, to finish the second part. then the 1/2 just
(-4,-8) bring down and would not be touched in this problem because
we would want it "skinny"
The homework for today is pg. 41 (15-20)
find the
1 y-intercept
2 zeros
3 vertex
a b c
1. f(x)=x^2-6x+8
6/36-4*8
6+2 or 6-2 which also 4 or 2 y-intercept (0,8)
2 2
2. (x^2-6x+9)+8-9
(x-3) (x-3)-1
(x-3)^2-1
(4,0) (2,0)
Friday, October 15, 2010
Thursday, October 14, 2010
Wednesday, October 6, 2010
Notes for 10/06/2010
''''''''___
i=-/-1
i2=-1
i3=-i
i4=1
Bell Ringer
3+4i...(2+i)
-----...------
(2-i)...(2+i)
4-2i+2i-i2
4-(-1)=5
6+3i+8i+4i2
6+11i+4(-1)
6-4+11i
2+11i
-------
...5
i2+2i3.....i
--------..---
.....i.........i
i3+2i4
-------
...i2
-i+2
------
...i
-1
---
-1
(2-i)
-----
.-1
-2+i
H.W.
Page. 28
#19-30
-try useing a calculater
''''''''___
i=-/-1
i2=-1
i3=-i
i4=1
Bell Ringer
3+4i...(2+i)
-----...------
(2-i)...(2+i)
4-2i+2i-i2
4-(-1)=5
6+3i+8i+4i2
6+11i+4(-1)
6-4+11i
2+11i
-------
...5
i2+2i3.....i
--------..---
.....i.........i
i3+2i4
-------
...i2
-i+2
------
...i
-1
---
-1
(2-i)
-----
.-1
-2+i
H.W.
Page. 28
#19-30
-try useing a calculater
Tuesday, October 5, 2010
Agenda
I Bell Ringer
II Finding and Manipulating Complex Conjugates
III Factoring of Quadratic Functions
Objective: Students will find and manipulate complex conjugates
Big Picture: Mathematics will find a solution to the unsolvable. Even if they have to make it up.
Bell Ringer
Using the quadratic formula
- Find the zeros in:
10x^2-5x+20
2x^2+4x+15
answers:
1+- square root of 31i /4
-4+-2 square root of 26i / 4
ex 1- add
4 + 2i
+ ( 7 - 3i )
------------
11 - 1i
ex 2- subtract
7 + 8i
- ( 8 + 2i )
-----------
-1 + 6i
ex 3- multiply
( 7 + 8i ) ( 7 - 8i )
49 - 56i + 56i - 64 (i^2)
49 + 64 = 113
ex 4- divide
3 + 4i (2 + 5i)
____ _____
2 - 5i (2 + 5i)
*do the distributive property or f.o.i.l.
-14 + 23
______
29
Homework- page 28 #'s 1-10
I Bell Ringer
II Finding and Manipulating Complex Conjugates
III Factoring of Quadratic Functions
Objective: Students will find and manipulate complex conjugates
Big Picture: Mathematics will find a solution to the unsolvable. Even if they have to make it up.
Bell Ringer
Using the quadratic formula
- Find the zeros in:
10x^2-5x+20
2x^2+4x+15
answers:
1+- square root of 31i /4
-4+-2 square root of 26i / 4
ex 1- add
4 + 2i
+ ( 7 - 3i )
------------
11 - 1i
ex 2- subtract
7 + 8i
- ( 8 + 2i )
-----------
-1 + 6i
ex 3- multiply
( 7 + 8i ) ( 7 - 8i )
49 - 56i + 56i - 64 (i^2)
49 + 64 = 113
ex 4- divide
3 + 4i (2 + 5i)
____ _____
2 - 5i (2 + 5i)
*do the distributive property or f.o.i.l.
-14 + 23
______
29
Homework- page 28 #'s 1-10
Sunday, October 3, 2010
im confused with the domain and stuff. i don't know how to do the hw
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